LINE, SURFACE AND VOLUME INTEGRALS
R
y
C
x
dx
dy
dr
nˆds
Figure 11.11 A closed curveCin thexy-plane bounding a regionR.Vectors
tangent and normal to the curve at a given point are also shown.
The surface integral overS 1 is easily evaluated. Remembering that the normal to the
surface points outward from the volume, a surface element onS 1 is simplydS=−kdx dy.
OnS 1 we also havea=(y−x)i+x^2 k,sothat
I=−
∫
S 1
a·dS=
∫∫
R
x^2 dx dy,
whereRis the circular region in thexy-plane given byx^2 +y^2 ≤a^2. Transforming to plane
polar coordinates we have
I=
∫∫
R′
ρ^2 cos^2 φ ρ dρ dφ=
∫ 2 π
0
cos^2 φdφ
∫a
0
ρ^3 dρ=
πa^4
4
.
It is also interesting to consider the two-dimensional version of the divergence
theorem. As an example, let us consider a two-dimensional planar regionRin
thexy-plane bounded by some closed curveC(see figure 11.11). At any point
on the curve the vectordr=dxi+dyjis a tangent to the curve and the vector
nˆds=dyi−dxjis a normal pointing out of the regionR. If the vector fieldais
continuous and differentiable inRthen the two-dimensional divergence theorem
in Cartesian coordinates gives
∫∫
R
(
∂ax
∂x
+
∂ay
∂y
)
dx dy=
∮
a·nˆds=
∮
C
(axdy−aydx).
LettingP=−ayandQ=ax, we recover Green’s theorem in a plane, which was
discussed in section 11.3.
11.8.1 Green’s theorems
Consider two scalar functionsφandψthat are continuous and differentiable in
some volumeVbounded by a surfaceS. Applying the divergence theorem to the