HIGHER-ORDER ORDINARY DIFFERENTIAL EQUATIONS
f(x)=0:
an(x)
dny
dxn
+an− 1 (x)
dn−^1 y
dxn−^1
+···+a 1 (x)
dy
dx
+a 0 (x)y=0. (15.2)
To determine the general solution of (15.2), we must findnlinearly independent
functions that satisfy it. Once we have found these solutions, the general solution
is given by a linear superposition of thesenfunctions. In other words, if then
solutions of (15.2) arey 1 (x),y 2 (x),...,yn(x), then the general solution is given by
the linear superposition
yc(x)=c 1 y 1 (x)+c 2 y 2 (x)+···+cnyn(x), (15.3)
where thecmare arbitrary constants that may be determined ifnboundary
conditions are provided. The linear combinationyc(x) is called thecomplementary
functionof (15.1).
The question naturally arises how we establish that anynindividual solutions to
(15.2) are indeed linearly independent. Fornfunctions to be linearly independent
over an interval, there must not existanyset of constantsc 1 ,c 2 ,...,cnsuch that
c 1 y 1 (x)+c 2 y 2 (x)+···+cnyn(x) = 0 (15.4)
over the interval in question, except for the trivial casec 1 =c 2 =···=cn=0.
A statement equivalent to (15.4), which is perhaps more useful for the practical
determination of linear independence, can be found by repeatedly differentiating
(15.4),n−1 times in all, to obtainnsimultaneous equations forc 1 ,c 2 ,...,cn:
c 1 y 1 (x)+c 2 y 2 (x)+···+cnyn(x)=0
c 1 y 1 ′(x)+c 2 y 2 ′(x)+···+cnyn′(x)=0
..
.
c 1 y( 1 n−1)(x)+c 2 y 2 (n−1)+···+cny(nn−1)(x)=0,
(15.5)
where the primes denote differentiation with respect tox. Referring to the
discussion of simultaneous linear equations given in chapter 8, if the determinant
of the coefficients ofc 1 ,c 2 ,...,cnis non-zero then the only solution to equations
(15.5) is the trivial solutionc 1 =c 2 =···=cn= 0. In other words, thenfunctions
y 1 (x),y 2 (x),...,yn(x) are linearly independent over an interval if
W(y 1 ,y 2 ,...,yn)=
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
y 1 y 2 ... yn
y 1 ′ y 2 ′
..
.
..
.
..
.
..
.
y 1 (n−1) ... ... yn(n−1)
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
= 0 (15.6)
over that interval;W(y 1 ,y 2 ,...,yn) is called theWronskianof the set of functions.
It should be noted, however, that the vanishing of the Wronskian does not
guarantee that the functions are linearly dependent.