SERIES SOLUTIONS OF ORDINARY DIFFERENTIAL EQUATIONS
Settingz= 0, all terms in the sum withn>0 vanish, implying that
[σ(σ−1) +s(0)σ+t(0)]a 0 =0,
which, since we requirea 0 = 0, yields theindicial equation
σ(σ−1) +s(0)σ+t(0) = 0. (16.16)
This equation is a quadratic inσand in general has two roots, the nature of
which determines the forms of possible series solutions.
The two roots of the indicial equation,σ 1 andσ 2 , are called theindicesof
the regular singular point. By substituting each of these roots into (16.15) in
turn and requiring that the coefficients of each power ofzvanish separately, we
obtain a recurrence relation (for each root) expressing eachanas a function of
the previousar(0≤r≤n−1). We will see that the larger root of the indicial
equation always yields a solution to the ODE in the form of a Frobenius series
(16.12). The form of the second solution depends, however, on the relationship
between the two indicesσ 1 andσ 2. There are three possible general cases: (i)
distinct roots not differing by an integer; (ii) repeated roots; (iii) distinct roots
differing by an integer (not equal to zero). Below, we discuss each of these in turn.
Before continuing, however, we note that, as was the case for solutions in
the form of a simple power series, it is always worth investigating whether a
Frobenius series found as a solution to a problem is summable in closed form
or expressible in terms of known functions. We illustrate this point below, but
the reader should avoid gaining the impression that this is always so or that, if
one worked hard enough, a closed-form solution could always be found without
using the series method. As mentioned earlier, this isnotthe case, and very often
an infinite series solution is the best one can do.
16.3.1 Distinct roots not differing by an integer
If the roots of the indicial equation,σ 1 andσ 2 , differ by an amount that is not
an integer then the recurrence relations corresponding to each root lead to two
linearly independent solutions of the ODE:
y 1 (z)=zσ^1
∑∞
n=0
anzn,y 2 (z)=zσ^2
∑∞
n=0
bnzn,
with both solutions taking the form of a Frobenius series. The linear independence
of these two solutions follows from the fact thaty 2 /y 1 is not a constant since
σ 1 −σ 2 is not an integer. Becausey 1 andy 2 are linearly independent, we may use
them to construct the general solutiony=c 1 y 1 +c 2 y 2.
We also note that this case includes complex conjugate roots whereσ 2 =σ 1 ∗,
sinceσ 1 −σ 2 =σ 1 −σ∗ 1 =2iImσ 1 cannot be equal to a real integer.