SPECIAL FUNCTIONS
and hence that theHn(x) satisfy the Hermite equation
y′′− 2 xy′+2ny=0,
wherenis an integer≥0.
Use Φ to prove that
(a) Hn′(x)=2nHn− 1 (x),
(b)Hn+1(x)− 2 xHn(x)+2nHn− 1 (x)=0.
18.6 A charge +2qis situated at the origin and charges of−qare situated at distances
±afrom it along the polar axis. By relating it to the generating function for the
Legendre polynomials, show that the electrostatic potential Φ at a point (r, θ, φ)
withr>ais given by
Φ(r, θ, φ)=
2 q
4 π 0 r
∑∞
s=1
(a
r
) 2 s
P 2 s(cosθ).
18.7 For the associated Laguerre polynomials, carry through the following exercises.
(a) Prove the Rodrigues’ formula
Lmn(x)=
exx−m
n!
dn
dxn
(xn+me−x),
taking the polynomials to be defined by
Lmn(x)=
∑n
k=0
(−1)k
(n+m)!
k!(n−k)!(k+m)!
xk.
(b) Prove the recurrence relations
(n+1)Lmn+1(x)=(2n+m+1−x)Lmn(x)−(n+m)Lmn− 1 (x),
x(Lmn)′(x)=nLmn(x)−(n+m)Lmn− 1 (x),
but this time taking the polynomial as defined by
Lmn(x)=(−1)m
dm
dxm
Ln+m(x)
or the generating function.
18.8 The quantum mechanical wavefunction for a one-dimensional simple harmonic
oscillator in itsnth energy level is of the form
ψ(x)=exp(−x^2 /2)Hn(x),
whereHn(x)isthenth Hermite polynomial. The generating function for the
polynomials is
G(x, h)=e^2 hx−h
2
=
∑∞
n=0
Hn(x)
n!
hn.
(a) FindHi(x)fori=1, 2 , 3 ,4.
(b) Evaluate by direct calculation
∫∞
−∞
e−x
2
Hp(x)Hq(x)dx,
(i) forp=2,q= 3; (ii) forp=2,q= 4; (iii) forp=q= 3. Check your
answers against the expected values 2pp!
√
πδpq.