PDES: SEPARATION OF VARIABLES AND OTHER METHODS
The first term depends only onrand the second and third terms (taken together)
depend only onθandφ. Thus (21.39) is equivalent to the two equations
1
R
d
dr
(
r^2
dR
dr
)
=λ, (21.40)
1
Θsinθ
d
dθ
(
sinθ
dΘ
dθ
)
+
1
Φsin^2 θ
d^2 Φ
dφ^2
=−λ. (21.41)
Equation (21.40) is a homogeneous equation,
r^2
d^2 R
dr^2
+2r
dR
dr
−λR=0,
which can be reduced, by the substitutionr=expt(and writingR(r)=S(t)), to
d^2 S
dt^2
+
dS
dt
−λS=0.
This has the straightforward solution
S(t)=Aexpλ 1 t+Bexpλ 2 t,
and so the solution to the radial equation is
R(r)=Arλ^1 +Brλ^2 ,
whereλ 1 +λ 2 =−1andλ 1 λ 2 =−λ. We can thus takeλ 1 andλ 2 as given by
and−(+1);λthen has the form(+ 1). (It should be noted that at this stage
nothing has been either assumed or proved about whetheris an integer.)
Hence we have obtained some information about the first factor in the
separated-variable solution, which will now have the form
u(r, θ, φ)=
[
Ar+Br−(+1)
]
Θ(θ)Φ(φ), (21.42)
where Θ and Φ must satisfy (21.41) withλ=(+1).
The next step is to take (21.41) further. Multiplying through by sin^2 θand
substituting forλ, it too takes a separated form:
[
sinθ
Θ
d
dθ
(
sinθ
dΘ
dθ
)
+(+1)sin^2 θ
]
+
1
Φ
d^2 Φ
dφ^2
=0. (21.43)
Taking the separation constant asm^2 , the equation in the azimuthal angleφ
has the same solution as in cylindrical polars, namely
Φ(φ)=Ccosmφ+Dsinmφ.
As before, single-valuedness ofurequires thatmis an integer; form= 0 we again
have Φ(φ)=Cφ+D.