PDES: SEPARATION OF VARIABLES AND OTHER METHODS
The first term depends only onrand the second and third terms (taken together)
depend only onθandφ. Thus (21.39) is equivalent to the two equations
1
Rd
dr(
r^2dR
dr)
=λ, (21.40)1
Θsinθd
dθ(
sinθdΘ
dθ)
+1
Φsin^2 θd^2 Φ
dφ^2=−λ. (21.41)Equation (21.40) is a homogeneous equation,r^2d^2 R
dr^2+2rdR
dr−λR=0,which can be reduced, by the substitutionr=expt(and writingR(r)=S(t)), to
d^2 S
dt^2+dS
dt−λS=0.This has the straightforward solution
S(t)=Aexpλ 1 t+Bexpλ 2 t,and so the solution to the radial equation is
R(r)=Arλ^1 +Brλ^2 ,whereλ 1 +λ 2 =−1andλ 1 λ 2 =−λ. We can thus takeλ 1 andλ 2 as given by
and−(+1);λthen has the form(+ 1). (It should be noted that at this stage
nothing has been either assumed or proved about whetheris an integer.)
Hence we have obtained some information about the first factor in theseparated-variable solution, which will now have the form
u(r, θ, φ)=[
Ar+Br−(+1)]
Θ(θ)Φ(φ), (21.42)where Θ and Φ must satisfy (21.41) withλ=(+1).
The next step is to take (21.41) further. Multiplying through by sin^2 θandsubstituting forλ, it too takes a separated form:
[
sinθ
Θd
dθ(
sinθdΘ
dθ)
+(+1)sin^2 θ]
+1
Φd^2 Φ
dφ^2=0. (21.43)Taking the separation constant asm^2 , the equation in the azimuthal angleφhas the same solution as in cylindrical polars, namely
Φ(φ)=Ccosmφ+Dsinmφ.As before, single-valuedness ofurequires thatmis an integer; form= 0 we again
have Φ(φ)=Cφ+D.