APPLICATIONS OF COMPLEX VARIABLES
forward, in that, whatever the sign ofyat any particular pointz, the curvature
always has the opposite sign. Consequently the curve always bends towards the
z-axis, crosses it, and then bends towards the axis again. Thus the curve exhibits
oscillatory behaviour. Furthermore, as−zincreases, the curvature for any given
|y|gets larger; as a consequence, the oscillations become increasingly more rapid
and their amplitude decreases.
25.6.2 Series solution of Stokes’ equation
Obtaining a series solution of Stokes’ equation presents no particular difficulty
when the methods of chapter 16 are used. The equation, written in the form
d^2 y
dz^2
−zy=0,
has no singular points except atz=∞. Every other point in thez-plane is
an ordinary point and so two linearly independent series expansions about it
(formally with indicial valuesσ= 0 andσ= 1) can be found. Those aboutz=0
take the forms
∑∞
0 anz
nand∑∞
0 bnz
n+1. The corresponding recurrence relations
are
(n+3)(n+2)an+3=an and (n+4)(n+3)bn+3=bn,
andthetwoseries(witha 0 =b 0 = 1) take the forms
y 1 (z)=1+
z^3
(3)(2)
+
z^6
(6)(5)(3)(2)
+···,
y 2 (z)=z+
z^4
(4)(3)
+
z^7
(7)(6)(4)(3)
+···.
The ratios of successive terms for the two series are thus
an+3zn+3
anzn
=
z^3
(n+3)(n+2)
and
bn+3zn+4
bnzn+1
=
z^3
(n+4)(n+3)
.
It follows from the ratio test that both series are absolutely convergent for allz.
A similar argument shows that the series for their derivatives are also absolutely
convergent for allz. Any solution of the Stokes’ equation is representable as a
superposition of the two series and so is analytic for all finitez;itisthereforean
integral function with its only singularity at infinity.
25.6.3 Contour integral solutions
We now move on to another form of solution of the Stokes’ equation (25.32), one
that takes the form of a contour integral in whichzappears as a parameter in