26.3 CARTESIAN TENSORS
O x 1x 2x′ 1x′ 2θθθFigure 26.1 Rotation of Cartesian axes by an angleθabout thex 3 -axis. The
three angles markedθand the parallels (broken lines) to the primed axes
show how the first two equations of (26.7) are constructed.coordinate systems, the transformation matrix is given by
Lij=e′i·ej.We note that the product of two rotations is also a rotation. For example,suppose thatx′i=Lijxjandx′′i=Mijx′j; then the composite rotation is described
by
x′′i=Mijx′j=MijLjkxk=(ML)ikxk,corresponding to the matrixML.
Find the transformation matrixLcorresponding to a rotation of the coordinate axes
through an angleθabout thee 3 -axis (orx 3 -axis), as shown in figure 26.1.Takingxas a position vector – the most obvious choice – we see from the figure that
the components ofxwith respect to the new (primed) basis are given in terms of the
components in the old (unprimed) basis by
x′ 1 =x 1 cosθ+x 2 sinθ,
x′ 2 =−x 1 sinθ+x 2 cosθ, (26.7)
x′ 3 =x 3.The (orthogonal) transformation matrix is thus
L=
cosθ sinθ 0
−sinθ cosθ 0
001
.
The inverse equations are
x 1 =x′ 1 cosθ−x′ 2 sinθ,
x 2 =x′ 1 sinθ+x′ 2 cosθ, (26.8)
x 3 =x′ 3 ,in line with (26.5).