262 CHAPTER 8 GEOMETRY FOR AMERICANS
Now we search for equal angles. Since the diagonal BC is a transversal intersecting
parallel lines AB and CD, we have
LDCB= LABC.
Likewise,
LACB = LDBC,
since AC and BD are also parallel. Finally, we use the trivial observation that BC = BC
to use ASA to conclude that
MCB � l:::.DBC.
Consequently, the opposite sides have equal length and the opposite angles LA and
LD have equal measure. To show that the other pair of opposite angles are equal , we
need to draw diagonal AD and show that MCD � l:::.DBA.
To show that adjacent angles are supplementary, we either appeal to Fact 8.2.6
(AC is a transversal of the parallel lines AB and CD), or use the fact that the sum of the
angles in a quadrilateral is 3600 (Example 2.3.5 on page 45).
Finally, once the second diagonal AD is drawn, observing vertical angles and us-
ing congruence easily yields (c). •
This example used perhaps the most productive technique: drawing an auxiliary
object. Sometimes, as above, drawing a single line is enough to get the job done. This
method is powerful, but not always easy. It takes skill, experience, and luck to find the
right objects to add to a given figure. And if you add too many objects, your figure
becomes hopelessly confused. Always let the penultimate step be your guide, and keep
in mind what "natural" entities will help you. Triangles? Circles? Symmetry?
Here's an easy exercise.
8.2.10 A triangle is isosceles if two of its sides have equal length. Prove that if a
triangle is isosceles, the angles opposite the equal sides have equal measure.
8.2. 11 Let ABC be isosceles, with AB = AC. We call A the vertex angle of the isosce
les triangle, and Band C are called the base angles. A nearly trivial consequence of
Fact 8.2.10 is
B =C = 90 - A/2;
in other words, the base angles of an isosceles triangle are complementary to half
the vertex angle (two angles are called complementary if they sum to a right angle;
contrast this with supplementary angles.)