Physical Chemistry Third Edition

(C. Jardin) #1

1124 27 Equilibrium Statistical Mechanics. III. Ensembles


Exercise 27.1
Choose several different functions ofEsuch as sin(E), cos(E),E,E^2 , and so on, and show that
they do not satisfy Eq. (27.1-5). Show that the function of Eq. (27.1-6) does satisfy this relation.

We can derive Eq. (27.1-6). Letxandyrepresent the two subsystem energies, so
that

p(x+y)p(z)p(x)p(y) (27.1-7)

wherex+yz. By the chain rule (see Appendix B),

dp
dx



dp
dz

∂z
∂x



dp
dx

p(y) (27.1-8a)

dp
dy



dp
dz

∂z
∂y



dp
dy

p(x) (27.1-8b)

Sincezx+y,∂z/∂y∂z/∂x1, and we can write

dp
dx

p(y)

dp
dy

p(x) (27.1-9)

We divide byp(x)p(y):

1
p(x)

dp
dx



1

p(y)

dp
dy

(27.1-10)

We have separated the variablesxandy. A function ofxthat equals a function ofyfor
all values of the independent variablesxandymust be a constant function ofx, since
ycan be held fixed whilexvaries. We let the constant functions equal−β, so that

1
p(x)

dp
dx

−βconstant (27.1-11)

We multiply bydxand do an indefinite integration

1
p(x)

dp
dx

dx

1

p

dpd[ln(p)]−βdx (27.1-12)

ln(p)−βx+ln(A) (27.1-13)

where ln(A) is a constant of integration. We take antilogarithms:

pAe−βx (27.1-14)

which is the same as Eq. (27.1-6), withxreplaced byE.

The Canonical Partition Function


We now need to eliminate the parametersAandβfrom the distribution shown in
Eq. (27.1-14). The total number of systems in the ensemble is fixed, so that

k

nkn (27.1-15)
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