Physical Chemistry Third Edition

(C. Jardin) #1
158 4 The Thermodynamics of Real Systems

PROBLEMS


Section 4.1: Criteria for Spontaneous Processes
and for Equilibrium: The Gibbs and Helmholtz
Energies


4.1If a simple system is somehow maintained at constant
SandP, show that its enthalpy cannot increase.
4.2 a.Calculate∆S◦and∆H◦for the vaporization of
1.000 mol of water at 298.15 K from the data in
Table A.8 in the appendix.
b. Calculate∆G◦for the vaporization of 1.000 mol of
water at 298.15 K.
c.Assume that both∆S◦and∆H◦for the vaporization of
water are temperature-independent. Find the temperature
at which∆G◦∆H◦−T∆S◦vanishes. If your
assumption were correct, this should be the temperature
at which liquid water and water vapor are at equilibrium
if the pressure is 1.000 bar.
d.Assume thatCP, mis temperature-independent
for both the solid and the liquid and find the
temperature at which∆G◦∆H◦−T∆S◦
vanishes.

4.3Consider the reaction at 298.15 K:

2H 2 (g)+O 2 (g)−→2H 2 O(l)

a.Calculate the value of∆H◦for this reaction.
b.Assume that∆H◦is temperature-independent. If the
heat from this reaction is used to power a steam turbine
with an efficiency that is 60.0% as great as that of a
Carnot engine operating between 200.0◦C and
400.0◦C, find the maximum amount of work that
can be done by the combustion of 2.000 mol of
hydrogen gas.
c.Calculate∆G◦for this reaction at 298.15 K from∆H◦
and∆S◦.
d.This reaction is carried out in fuel cells in spacecraft.
Calculate the maximum amount of net work that can be
done on the surroundings by the reaction of 2.000 mol of
hydrogen gas at 298.15 K. Calculate the total amount of
work that can be done on the surroundings. Comment
on the comparison between your results from parts b
and d.

4.2 Fundamental Relations for Closed Simple Systems


Thermodynamics includes a number of useful relations that allow one variable to be
replaced by another to which it is equal but which can be more easily evaluated. In this
section we obtain several such relations based on expressions for the differentials of
state functions. For a closed simple system and for reversible processes the first law of
thermodynamics is

dUdqrev−PdV (closed simple system) (4.2-1)

and the second law is

dS

dqrev
T

(closed simple system) (4.2-2)

Combination of these equations using the fact thatTcannot be negative gives an
important relation fordUfor reversible processes in a simple closed system:

dUTdS−PdV
(simple closed system;
reversible processes)

(4.2-3)

This equation is restricted to reversible changes of state becausedqrevwas used in its
derivation and becausePP(transmitted) was assumed.
Free download pdf