242 6 The Thermodynamics of Solutions
EXAMPLE 6.2
Calculate the Gibbs energy change of mixing, the entropy change of mixing, the enthalpy
change of mixing, and the volume change of mixing for a solution of 1.200 mol of benzene
and 1.300 mol of toluene at 20.00◦C. Assume the solution to be ideal.
Solution
∆GmixRT[(1.200 mol) ln(0.4800)+(1.300 mol) ln(0.5200)]−4219 J
∆Smix−R[(1.200 mol) ln(0.4800)+(1.300 mol) ln(0.5200)] 14 .39JK−^1
∆Hmix 0
∆Vmix 0
We can obtain expressions for other partial molar quantities from the expression for
the chemical potential. For example, Eq. (4.5-14) for the partial molar entropy is
S ̄i−
(
∂μi
∂T
)
P,n
(6.1-19)
Application of this equation to Eq. (6.1-1) gives
S ̄i−
(
∂μ∗i
∂T
)
P,n
−Rln(xi)
S ̄iS∗m,i−Rln(xi) (ideal solution) (6.1-20)
whereS∗m,iis the molar entropy of pure substancei.
Exercise 6.4
In the same way that Eq. (6.1-20) was derived, obtain the relations for the partial molar volume
and partial molar enthalpy of components of an ideal solution:
V ̄iVm,∗i (ideal solution) (6.1-21)
H ̄iHm,∗i (ideal solution) (6.1-22)
Molecular Structure and Ideal Solutions
It is found experimentally that Raoult’s law applies most nearly to liquid solutions in
which the substances have molecules of similar size, shape, and polarity. The expla-
nation for this fact is that if two substances have similar molecules, a molecule of one
substance attracts or repels molecules of the other substance in much the same way as
molecules of the same substance. The similarity of interaction allows the molecules
to mix randomly in a solution without changing the volume or the enthalpy just as
noninteracting molecules mix randomly in a dilute gas mixture.