322 7 Chemical Equilibrium
It is customary to specify the acidity of a solution in terms of the pH, which has
been variously defined. We would like to use the definitionpH−log 10[
a(
H+
)]
−log 10(
γ(
H+
)
m(
H+
)
m◦)
(desired
definition) (7.3-10)where log 10 denotes the logarithm to the base 10 (thecommon logarithm). The activity
coefficientγ(H+) cannot be measured, but if it can be approximated in some way we
can use Eq. (7.3-10) as a working equation.Exercise 7.8
Find the pH of the solution in Example 7.11.EXAMPLE7.12
a.Find the value of the equilibrium constant at 298.15 K for the ionization of acetic acid.
b.Find the percentage of acetic acid molecules that ionize and the pH in a solution prepared
from 0.100 mol of acetic acid and 1.000 kg of water and maintained at 298.15 K. Use the
Davies equation to estimate activity coefficients. Neglect any H+ions contributed by the
ionization of water.
Solution
a.Write the ionization equation in the formHAH++A−∆G◦ 0 +(− 369 .31 kJ mol−^1 )−(− 396 .46 kJ mol−^1 )
27 .15 kJ mol−^1Kexp(
−27,150 J mol−^1
(8.3145 J K−^1 mol−^1 )(298.15 K)) 1. 752 × 10 −^5b.Letxm(H+)/m◦m(A−)/m◦. First assume that all activity coefficients equal 1.1. 752 × 10 −^5 x^2
(0. 100 −x)x^2 +(1. 752 × 10 −^5 )x− 1. 752 × 10 −^6 0x
− 1. 752 × 10 −^5 ±√
(1. 752 × 10 −5)2+4(1. 752 × 10 −^6 )
2
1. 315 × 10 −^3This corresponds to an ionic strength of 1.315× 10 −^3 mol kg−^1. From the Davies
equationlog 10 (γ±)− 0. 510( √
0. 001315
1 +√
0. 001315−(0.30)(0.001315))− 0. 01523