8.2 Electrochemical Cells 357
0
(
∂G
∂ξ
)
dξ
2 μ(HCl)+ 2 μ(Ag)−μ(H 2 )− 2 μ(AgCl)+ 2 μ(e−(L))− 2 μ(e−(R))dξ
(8.2-5)
which is equivalent to
0
(
∂Gchem
∂ξ
)
T,P
dξ+ 2 μchem(e−(L))−μchem(e−(R))+Fφ(R)−Fφ(L)dξ
(8.2-6)
whereGchemincludes the chemical potentials of substances other than electrons. The
partial derivative is equal to
(
∂Gchem
∂ξ
)
T,P
2 μ(HCl)+ 2 μ(Ag)−μ(H 2 )− 2 μ(AgCl) (8.2-7)
All of these substances are electrically neutral, so only the chemical parts of these
chemical potentials are included. The electric potential occurs only in the chemical
potential expression of the electrons. If the reaction equation of Eq. (8.2-3) were used,
the same equation would result since the electric potential terms of the H+and the Cl−
would cancel.
Exercise 8.2
Write the equation for
(
∂Gchem
∂ξ
)
T,P
based on Eq. (8.2-3) and show that it is identical to
Eq. (8.2-6).
Both terminals are made of platinum and are at the same temperature and pressure,
so the chemical parts of the chemical potential of the electrons are the same at the two
terminals, and we can write from Eq. (8.1-5)
0
(
∂Gchem
∂ξ
)
T,P
+ 2 FE (8.2-8)
whereEis thecell voltage, defined by
Eφ(R)−φ(L) (8.2-9)
This corresponds to our second convention:The cell voltage is defined as the electric
potential of the right electrode minus that of the left electrode.
Since electrons are negative, a positive value ofEmeans that the chemical potential
of the electron is larger in the left electrode. If a passive circuit (one that does not exert
its own voltage) is connected between the terminals, electrons will move spontaneously
from the left terminal to the right terminal through this circuit. The cell reaction proceeds
spontaneously in the direction in which we wrote it. IfEis negative, the reverse of the
cell reaction proceeds spontaneously and electrons move spontaneously from right to
left in the external circuit.
Equation (6.3-6) relates the chemical potential of each uncharged substance to its
activity:
μiμ◦i+RTln(ai) (uncharged substance) (8.2-10)