22 1 The Behavior of Gases and Liquids
c.Find the pressure of 1.000 mol of nitrogen at a volume of 1.000 L and a temperature of
298.15 K using the van der Waals equation of state. Find the pressure of an ideal gas under
the same conditions.
Another common equation of state is thevirial equation of state:
PVm
RT
1 +
B 2
Vm
+
B 3
Vm^2
+
B 4
Vm^3
+ ··· (1.3-3)
which is a power series in the independent variable 1/Vm. TheBcoefficients are called
virial coefficients. The first virial coefficient,B 1 , is equal to unity. The other virial
coefficients must depend on temperature in order to provide an adequate representation.
Table A.4 gives values of the second virial coefficient for several gases at several
temperatures.
An equation of state that is a power series inPis called thepressure virial equation
of state:
PVmRT+A 2 P+A 3 P^2 +A 4 P^3 + ··· (1.3-4)
The coefficientsA 2 ,A 3 , etc., are calledpressure virial coefficientsand also must depend
on the temperature. It can be shown thatA 2 andB 2 are equal.
EXAMPLE 1.9
Show thatA 2 B 2.
Solution
We solve Eq. (1.3-3) forPand substituting this expression for eachPin Eq. (1.3-4).
P
RT
Vm
+
RT B 2
Vm^2
+
RT B 3
Vm^3
+ ···
We substitute this expression into the left-hand side of Eq. (1.3-4).
PVmRT+
RT B 2
Vm
+
RT B 3
Vm^2
+ ···
We substitute this expression into the second term on the right-hand side of Eq. (1.3-4).
PVmRT+A 2
RT
Vm
+
RT B 2
Vm^2
+
RT B 3
Vm^3
+ ···
If two power series in the same variable are equal to each other for all values of the variable,
the coefficients of the terms of the same power of the variable must be equal to each other.
We equate the coefficients of the 1/Vmterms and obtain the desired result:
A 2 B 2
Exercise 1.8
Show thatA 3
1
RT
(
B 3 −B^22
)
.