690 16 The Principles of Quantum Mechanics. II. The Postulates of Quantum Mechanics
The operator for|L|, the magnitude of the angular momentum, is not usable
since
|L|(L^2 )^1 /^2 (L^2 x+L^2 y+L^2 z)^1 /^2 (16.3-15)
and we have no procedure for unscrambling the square root when the operator is
formed. To obtain information about the magnitude of the angular momentum we will
use theL^2 operator.
Exercise 16.3
a.Construct the operator forL̂x.
b.Construct the operator forL̂y.
c.Construct the operator forL^2 z(the square of the operator forLz).
It is sometimes useful to have operator expressions for commutators.
EXAMPLE16.4
Find the operator equal to the commutator
[
̂x,p̂x
]
.
Solution
Operate on an arbitrary differentiable functionf(x):
[
̂x,̂px
]
f ̄
h
i
[
x
∂f
∂x
−
∂(xf)
∂x
]
− ̄
h
i
f
The operator equation is
[
̂x,p̂x
]
− ̄
h
i
ih ̄ (16.3-16)
Equation (16.3-16) is an important result. Some authors find the form of the operator
̂pxby postulating that this commutation relation must hold.
Exercise 16.4
a.Find the commutator [̂px,̂py].
b.Show that [
̂Lx,̂py
]
ih ̄̂pz (16.3-17)
If an operator is needed in another coordinate system, the operator is first constructed
in Cartesian coordinates and then transformed to the other coordinate system. For
example, if a particle moves in thexyplane, its position can be represented using the
polar coordinatesρandφ:
ρ
√
x^2 +y^2 (16.3-18)
φarctan(y/x) (16.3-19)