Physical Chemistry Third Edition

(C. Jardin) #1

690 16 The Principles of Quantum Mechanics. II. The Postulates of Quantum Mechanics


The operator for|L|, the magnitude of the angular momentum, is not usable
since

|L|(L^2 )^1 /^2 (L^2 x+L^2 y+L^2 z)^1 /^2 (16.3-15)

and we have no procedure for unscrambling the square root when the operator is
formed. To obtain information about the magnitude of the angular momentum we will
use theL^2 operator.

Exercise 16.3
a.Construct the operator forL̂x.
b.Construct the operator forL̂y.
c.Construct the operator forL^2 z(the square of the operator forLz).

It is sometimes useful to have operator expressions for commutators.

EXAMPLE16.4

Find the operator equal to the commutator

[
̂x,p̂x

]
.
Solution
Operate on an arbitrary differentiable functionf(x):

[
̂x,̂px

]
f ̄
h
i

[
x
∂f
∂x

∂(xf)
∂x

]
− ̄
h
i
f

The operator equation is
[
̂x,p̂x

]
− ̄
h
i
ih ̄ (16.3-16)

Equation (16.3-16) is an important result. Some authors find the form of the operator
̂pxby postulating that this commutation relation must hold.

Exercise 16.4
a.Find the commutator [̂px,̂py].
b.Show that [
̂Lx,̂py

]
ih ̄̂pz (16.3-17)

If an operator is needed in another coordinate system, the operator is first constructed
in Cartesian coordinates and then transformed to the other coordinate system. For
example, if a particle moves in thexyplane, its position can be represented using the
polar coordinatesρandφ:

ρ


x^2 +y^2 (16.3-18)

φarctan(y/x) (16.3-19)
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