80 2 Work, Heat, and Energy: The First Law of Thermodynamics
We can use the cycle rule, Eq. (B-15) of Appendix B, to write
(
∂H
∂P
)
T,n
−
(
∂H
∂T
)
P,n
(
∂T
∂P
)
H,n
−CPμJT (2.5-30)
The Joule–Thomson coefficient of an ideal gas vanishes because (∂H/∂P)T,nvan-
ishes. Joule and Thomson found that the Joule–Thomson coefficient is measurably
different from zero for ordinary gases at ordinary pressures. It depends on tempera-
ture and is positive at room temperature for most common gases except for hydrogen
and helium. Even for these gases it is positive at some range of temperatures below
room temperature. This means that for some range of temperature any gas cools on
expansion through a porous plug. Expansion of a gas can be used to cool the gas
enough to liquefy part of it, and the final step in the production of liquid nitrogen or
liquid helium is ordinarily carried out in this way.
EXAMPLE2.23
For air at 300 K and 25 atm,μJT0.173 K atm−^1. If a Joule–Thomson expansion is carried
out from a pressure of 50.00 atm to a pressure of 1.00 atm, estimate the final temperature if
the initial temperature is equal to 300 K.
Solution
∆T≈
(
∂T
∂P
)
T,n
∆P
(
0 .173 K atm−^1
)
(49 atm)8K
T 2 ≈292 K
The molecular explanation for the fact that the Joule–Thomson coefficient is pos-
itive at sufficiently low temperature is that at low temperatures the attractive inter-
molecular forces are more important than the repulsive intermolecular forces. When
the gas expands, work must be done to overcome the attractions and the potential
energy increases. If no heat is added, the kinetic energy decreases and the temperature
decreases.
PROBLEMS
Section 2.5: Enthalpy
2.38 Show that ifdUdq+dw,ifdUis exact, and ifdqis
inexact, thendwmust be inexact.
2.39 The work done on a nonsimple system such as a spring or a
rubber band is given by
dwP(transferred)dV+τdL
whereτis the tension force andLis the length of the
spring or rubber band. One must specify whether a heat
capacity is measured at constantτor at constantL,in
addition to specifying constantPor constantV. Find
a relation analogous to Eq. (2.5-11) relatingCP,τ
andCP, L.
2.40 a.The Joule–Thomson coefficient of nitrogen gas at
50 atm and 0◦C equals .044 K atm−^1. Estimate
the final temperature if nitrogen gas is expanded
through a porous plug from a pressure of 60.0 atm
to a pressure of 1.00 atm at 0◦C.
b. Estimate the value of (∂Hm/∂P)Tfor nitrogen gas at
50 atm and 0◦C. State any assumptions.