338 Chapter 4 Decimals
Analyze
- The18-gauge stainless steel is
0.0500 inch thick. Given - The 20-gauge stainless steel is
0.0375 inch thick. Given - How much thicker is the 18-gauge
stainless steel? Find
Form Phrases such as how much older, how much longer,and, in this case,how
much thicker,indicate subtraction. We translate the words of the problem to
numbers and symbols.
is equal to minus
0.0500 0.0375
SolveUse vertical form to perform subtraction:
9
StateThe 18-gauge stainless steel is 0.0125 inch thicker than the 20-gauge.
CheckWe can add to check the subtraction:
The result checks.
Difference
Subtrahend
Minuend
0.01
1
2
1
5
0.0375
0.0500
0.05
4
0
10
0
10
0.03 7 5
0.01 2 5
How much
thicker
the thickness of the
20-gauge stainless steel.
the thickness of the
18-gauge stainless steel
How much
thicker
Self Check 11
ALUMINUMHow much thicker
is 16-gauge aluminum that is
0.0508 inch thick than 22-gauge
aluminum that is 0.0253 inch
thick?
Now TryProblem 97
Sometimes more than one operation is needed to solve a problem involving
decimals.
EXAMPLE (^12) Conditioning ProgramsA 350-pound football player
lost 15.7 pounds during the first week of practice. During the second week, he
gained 4.9 pounds. Find his weight after the first two weeks of practice.
Analyze
- The football player’s beginning weight was 350 pounds. Given
- The first week he lost 15.7 pounds. Given
- The second week he gained 4.9 pounds. Given
- What was his weight after two weeks of practice? Find
Form The word lostindicates subtraction. The word gainedindicates addition. We
translate the words of the problem to numbers and symbols.
Self Check 12
WRESTLINGA 195.5-pound
wrestler had to lose 6.5 pounds
to make his weight class. After
the weigh-in, he gained back
3.7 pounds. What did he weigh
then?
Now TryProblem 103
is equal to minus plus
350 15.7 4.9
The player’s weight after
two weeks of practice
the second-week
weight gain.
the first-week
weight loss
his beginning
weight
The player’s weight after
two weeks of practice
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