Basic Mathematics for College Students

(Nandana) #1

832 Chapter 9 An Introduction to Geometry


If an exact answer contains p, we can use 3.14 as an
approximation, and complete the calculations by hand.
Or, we can use a calculator that has a pi key to find
an approximation.

p

Note that the volume formulas for a cone, cylinder,
and sphere contain a factor of p.
Cone
Cylinder
Sphere V^43 Pr^3

VPr^2 h

V^13 Pr^2 h

Find the volume of the cylinder shown here.
Give the exact answer and an approximation
to the nearest hundredth.
Since a radius is one-half of the diameter of
the circular base,. To find
the volume of the cylinder, proceed as follows:
This is the formula for the volume of a cylinder.
Substitute 4 for r,the radius of the base, and
3 for h,the height.
Evaluate the exponential expression.
Write the product so that Pis the last factor.
Use a calculator to do the multiplication.
The exact volume of the cylinder is 48pyd^3. To the nearest
hundredth, the volume is 150.80 yd^3.

150.7964474


 48 p

Vp(16)(3)

Vp( 4 )^2 ( 3 )

Vpr^2 h

r^12 8 yd4 yd

Find the volume of the sphere shown here. Give
the exact answer and an approximation to the
nearest tenth.

This is the formula for the
volume of a sphere.

Substitute 6 for r,the radius of the sphere.

Evaluate the exponential expression.

Multiply: 4(216) 864.

Divide:.
Use a calculator to do the multiplication.
The volume of the sphere is exactly 288pft^3. To the nearest tenth,
this is 904.8 ft^3.

904.7786842


864
 288 p 3  288




864


3


p




4


3


p(216)

V


4


3


p( 6 )^3

V


4


3


pr^3

3 yd

8 yd

6 ft
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