Programming in C

A Structure for Storing the Date 167

Program 9.1 Illustrating a Structure

// Program to illustrate a structure

#include <stdio.h>

int main (void)

{

struct date

{

int month;

int day;

int year;

};

struct date today;

today.month = 9;

today.day = 25;

today.year = 2004;

printf ("Today's date is %i/%i/%.2i.\n", today.month, today.day,

today.year % 100);

return 0;

}

Program 9.1 Output

Today's date is 9/25/04.

The first statement inside maindefines the structure called dateto consist of three inte-

ger members called month,day,and year. In the second statement, the variable todayis

declared to be of type struct date.The first statement simply defines what a date

structure looks like to the C compiler and causes no storage to be reserved inside the

computer.The second statement declares a variable to be of type struct dateand,

therefore,doescause memory to be reserved for storing the three integer values of the

variable today. Be certain you understand the difference between defining a structure

and declaring variables of the particular structure type.

After todayhas been declared, the program then proceeds to assign values to each of

the three members of today, as depicted in Figure 9.1.

TEAM FLY