Irodov – Problems in General Physics

6.6. Nuclear Reactions Binding energy of a nucleus: Eb = ZmH ± (A Z) mn — M, (6.6a) where Z is the charge of the nucleus (in u ...

(b)^017 (d, n) x; (c) Na 23 (p, x) Ne 20 ; (d) x (p, n) Ar 37. 6.254. Demonstrate that the binding energy of a nucleus with mass ...

proton outgoing at an angle 0 = 60° to the motion direction of the alpha-particle has a kinetic energy Tp = 2.09 MeV. 6.266. Mak ...

6.278. How much, in per cent, does the threshold energy of gam- ma quantum exceed the binding energy of a deuteron (Eb = 2.2 MeV ...

describing accumulation of that radionuclide N (t) per unit area of the foil's surface. The neutron flux density is J, the numbe ...

Relation between quantum numbers of strongly interacting particles: Q.--Tz - (^1) - 2 =Tz+ B 2 ±S (6.7d) Interactions of part ...

onstrate that the threshold kinetic energy of the particle m required for this reaction is defined by Eq. (6.7c). 6.303. A posit ...

Fig. 1. (a) A 3 2 1 g -1 5 5 4 1 2 3 4 ANSWERS AND SOLUTIONS 1A. v = 112-c = 3.0 km per hour. 1.2. (v) = 2v 0 (v 1 + v 2 )/(2vo ...

1.16. tm = vilvf ' ± v212 (^) ' 1.17. C D = I ji — 1. 1.18. See Fig. lb. 1.19.' (a) (v) aR/T = 50 cm/s; (b) 1(v)1 = 2R/r = 32 cm ...

Fig. 3. 1.41. R = a 3 12bs, w = all1+ (4bs 2 1a^3 )^2. 1.42. (a) w = 2av 2 , R = I/ 2 a; (b) w = bv^2 /a^2 , R = a 2 /b. 1.43. v ...

1.70. '1 V-21/(3W+ kg). 1.71. (a) w^1 — ("^11 — "^1 2) g-1-^2 m2wo ± m2 (b) F = rn 4 :+ 1 7: 1 (g— w^0 ). 1.72. w= 2g (2i — sina ...

ing this equation, we obtain k (ln no)/n; (b) w= g — lovoi +TO. 1.94. F = (mv„ 2 1R) cost a. 1.95. F = —mco 2 r, where r is the ...

1.114. (a) w' = co 2 R: (b) Fin = mco^2 r (2R/r)^2 — 1. 1.115. F cf= in(0 2 R V 5/9=8 N, (^) V 5+8g/3co^2 R..,^ =17 N. 1.116. (a ...

1.146. (al Fir= mg [sin a + (w 2 11 g) ccs al= 6 N. (b) co< <V g (k— tan a)// (1^ k tan cz) = 2 rad/s. 1.147. (a) V = (miv ...

acquires during the time dt is equal to dp = m dv dt•u = F dt. What follows is evident. 1.179. v = —u In (mo/m). 1.180. m = moe- ...

1.207. M= m V2ymsrir 2 /(ri±r 2 ), where ms is the mass of the Sun. 1.208. E = T U = —ymms12a, where ms is the mass of the Sun. ...

1.217. (a) Let us subdivide the spherical layer into small ele- ments, each of mass Sm. In this case the energy of interaction o ...

1.232. A ym (M 1 /R 1 M 2 /R 2 ) = 1.3.10 8 kJ, where M and R are the mass and the radius of the Earth and the Moon. 1.233. v 3 ...

Fig. 11. 1.269. N = 1 / 24 m01 2 sin 20. 1.270. cos 0 = 3 /2 gl 01. 1.271. Ax = 1 / 2 ka. 1.272. v' = 0) 0 1/V1 + 3m/M. 1.273. F ...

1.296. T = 11277 - 14o 2 1 (1 -.- r 2 /1 2 ), Al = 1 / 3 p.o 2 l^3 IE, where p is the density of copper. 1.297. AV'--= (1 — 2μl ...