Irodov – Problems in General Physics

(Joyce) #1

6.133. X = 154 pm.
6.134. (a) 843 pm for Al, 180 pm for Co; (b)^ 5 keV.
6.135. Three.
6.136. V = 15 kV.
6.137. Yes.
6.138. Z =1+2 ji(n —1) eV 1 13hR (n— 1/ 1 /V 2 )=29.
6.139. Z = 1 + 1/4A(.6/3R = 22, titanium.
6.140. Eb = 3 / (Z 1) 2 + 2nch/XL = 5.5 keV.
6.141. EL = hw (2nchoAX — 1) pi., 0.5 keV,^ where^ w =
= 3 /4R (Z 1)^2.
6.142. T = 214 AR (Z — 1)^2 — 2nchAK = 1.45 keV,^ v
=2.26.10 7 m/s.
6.143. (a) g = 2, with the exception of the singlet state, where
g = 0/0; (b) g = 1.
6.144. (a) —2/3; (b) 0; (c) 1; (d) 5/2; (e) 0/0.
6.145. (a) 1/12μB; (b) 2 V3/5μs; (c) (8/if -g) [LB.
6.146. Ms = 2
6.147. μ = (8/1/3)
6.148. p, = 31/7/5/5μB.
6.149. o.—(5 1/5/2) Rs.
6.150. M= h on.
6.151. 5 F 1.
6.152. e p,BI gB lh = 1.2-10^1 ° rad/s, where g is the Lando
factor.
6.153. F max max' laBiaZI = (3/1/8) Itiap,B/Cr^2
= 4.10-27 N.
6.154. F = 21- IL BIcr^2 = 3.10-26 N.
6.155. aB/az = 2T6I gJp.Bli (1 1 + 21 2 ) = 15 kG/cm.
6.156. (a) It does not split; (b) splits into 6 sublevels; (c) does
not split (g = 0).
6.157. (a) 58 ReV; (b) AE = 2g4BB = 145 lieV.
6.158. (a) Normal; (b) anomalous; (c) normal; (d) normal (both
terms have identical Land6 factors).
6.159. L = AE121ABB = 3;^1 F^3.
6.160. AX = X^2 eB/2nmc^2 = 35 pm.
6.161. B min = 4.0 kG.
6.162. B = hAoilgti,B = 3 kG.
6.163. (a) 2 .1 (the ratio of the corresponding Uncle factors);
(b) B = 2nchAX/gRAX 2 = 5.5 kG.
6.164. Act) = (±1.3, ±4.0, ±6.6)•10^10 s-1 , six components.
6.165. (a) Six (1) and four (2); (b) nine (1) and six (2).


6.166. Ace (^) (migi — ntsgs) ma maxeBlmc^ 1.0.10" s-^1.
6.167. ce = 4 If 241mci 2 = 1.57.10" s-^1 , where m is the mass
of the molecule.
6.168. 2 and 3.

Free download pdf