Let us compute some of the probabilities using The probability
(0 1) is numerically equal to the area under from 0 to
1, as shown in F igure 3.6(a). It is given by
The probability is obtained by computing the areaunder to the
right of 3. H ence,
The same probabilities can be obtained from by taking appropriate
differences, giving:
Let us note that there is no numerical difference between (0 1) and
(0 1) for continuous random variables, since ( 0) 0.
3.2.4 M ixed-Type D istribution
There are situations in which one encounters a random variable that is partially
discrete and partially continuous. The PDF given in Figure 3.7 represents such
1
0
FX(x)
x
Figure 3.7 A mixed-type probability distribution function,
46 Fundamentals of Probability and Statistics for Engineers
FX
x
Z x
1
fX
udu 0 ; forx< 0 ;
1 eax; forx0.
8
<
:
3 : 15
fX 9 x).
P <X fX 9 x) x
x
P 0 <X 1
Z 1
0
fX
xdx 1 ea:
P 9 X>3) fX 9 x)
x
P X> 3
Z 1
3
fX
xdxe^3 a:
FX 9 x)
P
0 <X 1 FX
1 FX
0
1 ea 0 1 ea;
P
X> 3 FX
1FX
3 1
1 e^3 ae^3 a:
P <X
P X P X
FX 9 x)