Fundamentals of Probability and Statistics for Engineers

(John Hannent) #1
For part (b),

Figure 3.9 shows pX (x) for the discrete portion and fX (x) for the continuous
portion of X. They are given by:


and


;

Note again that the area under fX (x) is no longer one but is


To obtain P(X 2) and P(2 X 6), both the discrete and continuous
portions come into play, and we have, for part (a),


3 x

pX(x)
fX(x)

3 x

—^1
2e

—^1
3
—^1
3e
—^1
6e
(a) (b)

Figure 3. 9 (a) Partial probability mass function, pX (x), and (b) partial probability
density function, fX (x), of X, as described in Example 3.4

48 Fundamentals of Probability and Statistics for Engineers


P… 2 <X 6 †ˆFX… 6 †FX… 2 †

ˆ 1 

e^2
2



… 1 e^2 =^3 †ˆe^2 =^3 

e^2
2

:

pX…x†ˆ

1

2e

; atxˆ 3 ;
0 ; elsewhere;

8

<

:

fX…x†ˆ

dFX…x†
dx

ˆ

0 ; forx< 0 ;
1
3

ex=^3 ; for 0x<
1
6

ex=^3 ; forx 3 :

8

>>

>>

<

>>>

>:

3

1 pX… 3 †ˆ 1 

1

2e

:

> < 

P…X> 2 †ˆ

Z 1

2

fX…x†dx‡pX… 3 †

ˆ

1

3

Z 3

2

ex=^3 dx‡

1

6

Z 1

3

ex=^3 dx‡

1

2e
ˆe^2 =^3
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