PRACTICAL MATLAB® FOR ENGINEERS PRACTICAL MATLAB

Direct Current and Transient Analysis 145

3. W
   W

1f

2f

ft lb

ft lb

50 0 737 36 85

16 0 737 11 79

* ..

* ..

⋅

⋅

4. W
   W

1

2

kW h

kW

50 3 6 10 0 0000138

16 3 6 10 0 00000444

6

6

/.*.

/.*.



 hh

MATLAB Solution

>> R1=3; R2=2; C1=1; C2=2; VC=10;

>> VC1=VC; VC2=(R2/(R1+R2))*VC;

>> W1_J=0.5*C1*VC1^2,W2_J=0.5*C2*VC2^2

W1 _ J =

50

W2 _ J =

16

FIGURE 2.41

Electrical network of Example 2.5.

R 3 = 4 Ω

R 1 = 3 Ω

R 2 = 2 Ω

C 1 = 1 F

C 2 = 2 F

V = 10 V

FIGURE 2.42

Equivalent DC circuit of Figure 2.41.

VC 1 = 10 V

VC 2 =VR 2

R 1 = 3 Ω R 2 = 2 Ω

C 1 = 1 F

V = 10 V