PRACTICAL MATLAB® FOR ENGINEERS PRACTICAL MATLAB

270 Practical MATLAB® Applications for Engineers

ANALYTICAL Solution

X

jC j

C() j

(/ )





 


11

10 1 40

4

··

Ω

X = 3 − j4 (Ω)

Then, Z = X//R 2.

Z

X

X



* 


10

10

367 ∠Ω36.

MATLAB Solution

% Script file: imp _ Z

W = 10;

R1 = 3;

R2 = 10;

C = 1/40;

XC = -j/(W*C);

X = R1+XC;

Z = X*R2/(X+R2);

Zmag = abs(Z);

Phase = angle(Z);

Phase _ deg = Phase*360/(2*pi);

disp(‘^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^’)

disp(‘Magnitude of Z (in Ohms) and phase (in degrees) is given by :’);

Zmag

Phase _ deg

disp(‘^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^’)

The script fi le imp_Z is executed and the results are shown as follows.

FIGURE 3.51
Network of Example 3.3.

Z R 2 = 10 Ω

R 1 = 3 Ω

C = 1/40 F

w = 10 rad/s