PRACTICAL MATLAB® FOR ENGINEERS PRACTICAL MATLAB

Alternating Current Analysis 313

Xc = −j 3 Ω

XL = j 5 Ω

R = 3 Ω

30 90°

FIGURE 3.92

Network diagram of P.3.18.

V 1 = 100 0° V

+ –

V 2 = 100 90° V

+ –

Z 1 = j 25 Ω

Z 2 = j 25 Ω

Z 3 = −j 50 Ω

Z 5 = −j 50 Ω

Z 6 = −j 50 Ω

Z 4 = −j 25 Ω

I 1

I 3

I 2

FIGURE 3.91

Network diagram of P.3.16.