Fourier and Laplace 361
R.4.113 To gain additional experience, fi ve examples of DEs are presented and solved
manually, using the LT technique.
The following examples are solved for y(t) for each of the given DEs.
a. Example (#1)
Given the DE
240 020
dy t
dt
yt y
()
() with IC (initial condition) ( )
ANALYTICAL Solution
Taking the LT of the given equation results in
22040[()sY s Y s ] ()
sY s() 20 4 Ys() Ys()
2
2
then
sY s()^2200 Y s()
Ys s()(^2200 )
then
Ys
s
()^20
(^2)
taking the ILT
yt e ut
() 20 ^2 t ()
b. Example (#2)
Let the initial value of DE be
dyt
dt
yt
2
2 4
()
()
with the IC given by
y
dy t
dt t
()
()
00 and 0 8
ANALYTICAL Solution
Applying the LT to the preceding equation
sYs sy
dy t
dt
Ys
t
2
0
() ( ) 04
()
()
sYs s Ys
(^2) ()( ) 084 ()