Analog and Digital Filters 597
and the resulting network structure is illustrated in Figure 6.21.
Let us equate Equation 6.1 with Equation 6.2 resulting in the following:Hs
ss
ssss
ssss
ss()
1
69
46
1
46
46
23
46
2
22
22
2Hs
ss
ssss
ss()
1
69
46
1
1
23
46
2
22
+ 2LetZ
ss
ss23
46
2
2 , note that^()
()
1
2Z
Zs
ZsFIGURE 6.20
Structure for H(s) of R.14.144.Z 1 (s)Vi(s) Z 2 (s) Vo(s)FIGURE 6.21
Reduction of H(s) of Figure 6.20.Z 1 (s)
Z 2 (s)Vi(s) 1 Ω Vo(s)