Analog and Digital Filters 597
and the resulting network structure is illustrated in Figure 6.21.
Let us equate Equation 6.1 with Equation 6.2 resulting in the following:
Hs
ss
ss
ss
ss
ss
ss
()
1
69
46
1
46
46
23
46
2
2
2
2
2
2
Hs
ss
ss
ss
ss
()
1
69
46
1
1
23
46
2
2
2
+ 2
Let
Z
ss
ss
23
46
2
2 , note that^
()
()
1
2
Z
Zs
Zs
FIGURE 6.20
Structure for H(s) of R.14.144.
Z 1 (s)
Vi(s) Z 2 (s) Vo(s)
FIGURE 6.21
Reduction of H(s) of Figure 6.20.
Z 1 (s)
Z 2 (s)
Vi(s) 1 Ω Vo(s)