610 Practical MATLAB® Applications for Engineers
FIGURE 6.37
Circuit diagram of Example 6.3.
Vi(s) C = 1F Vo(s)
L = 1H
R = 1 Ω
The solutions of Example 6.3 are given by the script fi le shifting_LPF as follows:
ANALYTICAL Solution
Hs
R
sC
R
sC
sL
R
sC
R
sC
()
1
1
1
1
Hs
Vs
Vs
R
sC
R
sC
sL R
sC
o
i
()
()
()
^1
Hs
Vs
Vs
R
sC
sRL R
sC
L
C
o
i
()
()
()
Hs
Vs
Vs
R
sC sRL R
sC
L
C
o
i
()
()
()
Hs
Vs
Vs
R
s RLC Ls R
o
i
()
()
()
2 for 1RCL
Hs
Vs
Vs s s
o
i
()
()
()
1
(^21)
MATLAB Solution
% Script file: shifting _ LPF
% part(b), LPF with wn =1,R=L=C=1
num1=1;
den1= [1 1 1];
w = [0:.2:4];
H1 = freqs(num1,den1,w);