Lines, angles and polygons (Chapter 4) 103
5 Because of its symmetry, a regular pentagon can be constructed
from five isosceles triangles.
a Find the size of angleμat the centre O.
b Hence, findÁ.
c Hence, find the measure of one interior angle such as ABC.b
6 Repeat question 5 but use a regular decagon. Remember that a
decagon has 10 sides.
We have already seen that the sum of the interior angles of a triangle is 180 o.
Now consider finding the sum of the angles of a quadrilateral.
We can construct a diagonal of the quadrilateral as shown.
The red angles must add to 180 oand so must the green angles.
But these 6 angles form the 4 angles of the quadrilateral.
So, the sum of the interior angles of a quadrilateral is 360 o.
We can generalise this process to find the sum of the interior angles of any polygon.
Discovery 1 Angles of ann-sided polygon#endboxedheading
What to do:
1 Draw any pentagon ( 5 -sided polygon) and label one of its
vertices A. Draw in all the diagonals from A.
2 Repeat 1 for a hexagon, a heptagon ( 7 -gon), an octagon,
and so on, drawing diagonals from one vertex only.
3 Copy and complete the following table:
Polygon
Number
of sides
Number of
diagonals fromA
Number of
triangles
Angle sum
of polygon
quadrilateral 4 1 2 2 £ 180 o= 360o
pentagon
hexagon
octagon
20 -gon
4 Copy and complete the following statement:
“The sum of the interior angles of anyn-sided polygon is ......£ 180 o.”
D THE INTERIOR ANGLES OF A POLYGON [4.4]
A
B
C
f°
q°
A
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Y:\HAESE\IGCSE01\IG01_04\103IGCSE01_04.CDR Monday, 15 September 2008 11:55:57 AM PETER