Analysis of discrete data (Chapter 13) 291Example 7 Self Tutor
Class interval Frequency
0 - 9 2
10 - 19 31
20 - 29 73
30 - 39 85
40 - 49 28The table summarises the marks received by students for a Physics
examination out of 50.
a Estimate the mean mark.
b What is the modal class?
c Can the range of the data be found?Class interval f Mid-point (x) fx
0 - 9 2 4 : 5 9 : 0
10 - 19 31 14 : 5 449 : 5
20 - 29 73 24 : 5 1788 : 5
30 - 39 85 34 : 5 2932 : 5
40 - 49 26 44 : 5 1157 : 0
217 6336 : 5a Mean =P
fx
P
f=6336 : 5
217
¼ 29 : 2
b The modal class is 30 - 39 marks.
c3
85 £^10 is the
fraction of the
interval in which
the median is
found.No, as we do not know the smallest
and largest score.This formula is
.not
examinableTHE MEDIAN
We can estimate the median of a grouped data set by using acumulative
frequency graphorogive. This is done inChapter 17.The approximate median can also be calculated using a formula:median¼L+N
F
£I
whereL=the lower boundary for the class interval containing the
median
N=the number of scores in the median class needed to arrive
at the middle score
F=the frequency of the class interval containing the median
I=the class interval length.For example, inExample 7we notice that n= 217, so the median is the217 + 1
2
= 109th score.There are2 + 31 + 73 = 106 scores in the first 3 classes, so the median
class is 30 - 39.For discrete data, the lower and upper boundaries for the
class interval 30 - 39 are 29 : 5 and 39 : 5 , ) L=29: 5.N= 109¡106 = 3, F=85and I=10) the median¼ 29 :5+ 853 £ 10 ¼ 29 : 9TotalsIGCSE01
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100 100
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100 100
y:\HAESE\IGCSE01\IG01_13\291IGCSE01_13.CDR Thursday, 16 October 2008 9:47:27 AM PETER