Cambridge International Mathematics

(Tina Sui) #1
ANSWERS 737

4aBbCD=90o,BbDC=45o
bFroma, CBD=45o fangles in a triangleg
) ¢BCD is isosceles.
cDbEF=65o
6 Hint: A, B, C and D lie on a circle with centre O.
EXERCISE 27B.2
1aYes, one pair of opposite angles are supplementary.
bYes, AD subtends equal angles at B and C. c No.
dYes, opposite angles are supplementary.
eYes, one pair of opposite angles are supplementary.
fYes, AD subtends equal angles at B and C.
REVIEW SET 27A
1aa=72 ba=62 ca=61 da= 140
ea=45 f a=83 ga=80 ha=63
i a=45
3a 8 cm b 2 cm 5aDbBO=®
REVIEW SET 27B
1ax=86 bx=90 cx=79 dx=42
ex=55 f x=55
356 cm
5a i 90 o ii 90 o
bi 90 o¡® fradius tangent theoremg
ii ® fangle sum of triangleg
iii ® fangles on same arcg
6aBbCX=®,CbBX= ̄ b®+ ̄+°= 180o
EXERCISE 28A
1a 2 b^12 c 4 d^14 e 5 f^15
g 2 h^12 i 4 j^14 k 2 l^12
m 5 n ¡ 5 ono real solution p ¡ 1
2a 1012 b 10 ¡^12 c 1513 d 15 ¡^13 e 1914
f 19 ¡

(^14)
g 13
(^15)
h 13 ¡
(^15)
3a 4 b 3 c 4 d¼ 5 : 85
e¼ 4 : 47 f ¼ 3 : 98 g 2 h¼ 2 : 21
4a 16 b^14 c 8 d^18 e 9 f^19
g 4 h^18 i 32 j 251 k 27 l 271
EXERCISE 28B
1a 3 b 11 c 213 2a¡ 2 b ¡ 245 c 22
3a^19 b 9 c 271
4ax ¡^3 ¡^2 ¡1012 3
y 271 19 13 1 3 9 27
b,c
5a i¼ 1 : 6 ii ¼ 3 : 5 iii ¼ 0 : 7
bi¼ 1 : 62 ii ¼ 3 : 48 iii ¼ 0 : 707
cix¼ 2 : 3 ii x¼ 0 : 6 iiino solution
6ay=2x+1+3 b y=3x¡^2 ¡ 4
ciy=¡ 2 ¡x iiy=2x iii x=2¡y
diy= 2(3x) ii y=3^3 x
7a i ii 1
iii y=0
bi ii 0
iii y=¡ 1
ci ii^12
iii y=0
di ii 2
iii y=0
ei ii 4
iii y=3
fi ii 1
iii y=2
gi ii^23
iii y=^13
2 x
-2
2
-2
y
yx¡=¡¦()
yx¡=¡-¦()
yx¡=¡¦(- )
yx¡=¡2¦()
yx¡=¡¦(2 )
O
f(x)=( 1. 2 )x 1
y
x
y¡=¡0
O
y¡=¡-1
y
O x
f(x)= 2 x- 1
0.5
y
y¡=¡0 O x
f(x)= 2 x-^1
2
y¡=¡0
y
O x
f(x)= 2 x+^1
(^4) y¡=¡3
y
O x
f(x)= 3 + 2 x
1
y¡=¡2
1
y
O x
f(x)= 2 - 2 x
y¡=¡\Qe We
x
y
O
3
f(x)=^2 - x+^1
IB MYP_3 ANS
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Y:\HAESE\IGCSE01\IG01_an\737IB_IGC1_an.CDR Thursday, 20 November 2008 12:05:36 PM PETER

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