222 SOLUTIONSharmonicoscillator offrequency whoseenergylevels areThe average energy in the circuit is given by (withThe average energy is equally distributedbetween the capacitance and the
inductance:where V is the voltage across the capacitor (between points A and B; see
FigureS.4.96). We then haveIn the classical limitWe could equally well have derived the classical result by using the equipar-
tition theorem (see Problem4.42). For the single degree of freedom, there
is an average energy which, as noted, is divided between the capacitor
and inductor, soa)where is the charge on the capacitor. This is theHamiltonian of a