THERMODYNAMICS AND STATISTICAL PHYSICS 235The currentwhere is the electron charge. Therefore, we can express P from (S.4.103.5):Equating (S.4.103.6) with (S.4.103.3), we find the currentAlternatively, we cancalculate thecurrent byconsidering the electrons
leaving the metal as if theyhave akinetic energy high enough toovercome
the potential barrier.b) For one particle,where and are theenergies, and and thevolumes per particle,
of the gas and solid, respectively.Since we canrewrite (S.4.103.8)
in the formSubstituting(S.4.103.9)into theClausius-Clapeyronequation (seeProblemwe obtain
We may rewrite(S.4.103.11) as
Integrating,we recover (S.4.103.2):
whereAis someconstant, or
4.57),