The Chemistry Maths Book, Second Edition

(Grace) #1

324 Chapter 11First-order differential equations


and for the H


2

2 O


2

reaction,


The mechanism of a chemical reaction is in general complex, proceeding through


several elementary kinetic steps, that may be consecutive, competitive, or both, and it is


the task of the kineticist to unravel the mechanism and to relate the rate of the overall


chemical reaction to the rates of the elementary steps. It is found by experiment that


the overall rate may depend on the amounts of all the chemical species present


at any time, both reactant and product, as well as on the temperature, the pressure,


and the nature of the container. We consider here only the very simplest reactions,


those whose rates depend only on the amounts of the reactants; we represent such a


reaction by


aA 1 + 1 bB 1 +1-1→products (11.29)


It is found from experiment that the rate of the reaction has the form


v 1 = 1 k[A]


α

[B]


β

= (11.30)


where kis called the rate constantof the reaction, and the numbers α, β, =, define the


orderof the reaction. The exponent αis called the order with respect to reactant A,


βis the order with respect to B, =, and the sumα 1 + 1 β 1 +1-is called the order of the


reaction. The cases considered are


(1)A 1 → 1 products first order


(2)2A 1 → 1 products second order


(3)A 1 + 1 B 1 → 1 products second order


(1) The first-order process: A 1 → 1 products


The rate equationis


(11.31)


or, if the concentration [A]is represented by the variable x,


(11.32)


This is the differential equation discussed in Examples 3.20 and 11.1, and the solution


is that given in Example 11.4(ii). Thus, separating the variables and integrating,


ln 1 x 1 = 1 −kt 1 + 1 c or ln[A] 1 = 1 −kt 1 + 1 c (11.33)


dx


x


=−kdt,


dx


dt


=−kx


v=− =


d


dt


k


[]


[]


A


A


v=− =− =


1


2


1


2


22 2

d


dt


d


dt


d


dt


[] [] [ ]HOHO

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