2.5 Polynomials 45
EXAMPLE 2.17Case
The quadratic
2 x
21 − 18 x 1 + 181 = 1 2(x 1 − 1 2)
2has zero discriminant and the double root(two equal roots)x 1 = 1 2.
0 Exercises 47, 48
When the discriminant is negative, formula (2.20) requires the taking of the square
root of a negative number, and the result is not a real number. In this case the roots of
the quadratic are a pair of complex numbers involving the square root of
(see Section 8.2)
EXAMPLE 2.18Case
The quadratic
x
21 − 14 x 1 + 113
has a pair of complex roots x
1and x
2given by
The roots arex
11 = 121 + 13 iandx
21 = 121 − 13 iand the factorized form of the quadratic is
(x 1 − 1 x
1)(x 1 − 1 x
2).
0 Exercises 49, 50
0 Exercises 51, 52
For very large (‘large enough’) values of |x|the term in x
2in the quadratic
f(x) 1 = 1 ax
21 + 1 bx 1 + 1 cis very much larger in magnitude than the other two terms. Thus,
dividing the function byx
2,
This means that for large enough positive and negative values of x, the function behaves
like the simpler function ax
2, and can sometimes be replaced by it. In general for the
polynomial of degree n, equation (2.9),
fx
x
a
b
x
c
x
ax
()
22=+ + → as →±∞
xi=
±−
=±
436
2
23
bac
2−< 40.
−=−11:i
bac
2−= 40.