The Chemistry Maths Book, Second Edition

(Grace) #1

576 Chapter 20Numerical methods


EXAMPLE 20.11Find estimates of the integral by means of


Simpson’s rule (20.35) for 2 n 1 = 1 2, 4, 6,and 12.


We use the values of the integrand in Table 20.7 and construct Table 20.9.


Table 20.9 Simpson’s rule for


jx


j

f(x


j

)2n 1 = 122 n 1 = 142 n 1 = 162 n 1 = 112


0 0.0 0.000000 × 1 × 1 × 1 × 1


1 0.1 0.099005 × 4


2 0.2 0.192158 × 4 × 2


3 0.3 0.274179 × 4 × 4


4 0.4 0.340858 × 2 × 2


5 0.5 0.389400 × 4


6 0.6 0.418606 × 4 × 2 × 4 × 2


7 0.7 0.428838 × 4


8 0.8 0.421834 × 2 × 2


9 0.9 0.400372 × 4 × 4


10 1.0 0.367879 × 4 × 2


11 1.1 0.328017 × 4


12 1.2 0.284313 × 1 × 1 × 1 × 1


Totals 1.958737 3.819729 5.724269 11.446227


0.391747 0.381973 0.381618 0.381541


The exact value is 0.381536, and Simpson’s rule is accurate enough for many


applications even without correction.


0 Exercises 20–23


The Euler–MacLaurin formula


When the integrandf(x)can be expanded as a Taylor series in the intervala 1 ≤ 1 x 1 ≤ 1 b,


the approximate expression (20.32) for the trapezoidal rule can be replaced by the


Euler–MacLaurin formula


(20.36)



!


′− ′ −


!


′′′



′′′



!


B


h


ff B


h


ff B


h


2 nn

2

04

4

06

6

24 6


() ( ) (()ff


n

vv

−−


0




Z


a

b

nn

fxdx h f f f() =+++++f f













1


2


1


2


012 1




×=


h


I


3


Ixedx


x

==


−−

Z


0

1.2 2

Ixedx


x

=



Z


0

12. 2
Free download pdf