652 Solutions to exercises
Section 21.7
- (i) 3 a
2
1 − 12 a
3
(iii)
(iv)
- 11 − 1 e
− 2 R
(1 1 + 12 R 1 + 12 R
2
)
- (i) (ii) (iii) 1
3
2
3
2
7
55
1
2
1
25
,
Section 21.10
- (i)y 1 = 1 1.257x 1 + 1 2.727
(ii)σ
m1 = 1 0.084,σ
c1 = 1 0.615
- (i)ln(k 2 dm
3
1 mol
− 1
1 s
− 1
) 1
= 1 −1.076 1 × 110
4
(K 2 T ) 1 + 1 27.38
(ii)E
a1 = 1 89.5 1 kJ 1 mol
− 1
,
A 1 = 1 7.8 1 × 110
11
1 dm
3
1 mol
− 1
1 s
− 1
(iii)σ
m1 = 1 114.9;E
a1 = 1 89.5 1 ± 1 1.0 1 kJ 1 mol
− 1
σ
c1 = 1 0.355; 1
51 × 110
11
1 < 1 A 2 dm
3
1 mol
− 1
1 s
− 1
1 < 11111 × 110