Sams Teach Yourself C in 21 Days

{

newone[ctr] = orig[ctr];

}

}

6. The following is one of many possible answers:
   #include <stdio.h>
   #include <string.h>
   / function prototypes /
   char compare_strings( char , char );
   int main( void )
   {
   char a = “Hello”;
   char b = “World!”;
   char longer;
   longer = compare_strings(a, b);

printf( “The longer string is: %s\n”, longer );

return 0;

}

char * compare_strings( char * first, char * second)

{

int x, y;

x = strlen(first);

y = strlen(second);

if( x > y)

return(first);

else

return(second);

}

7. This exercise was on your own!
   8.a_stringis declared as an array of 10 characters, but it’s initialized with a string
   larger than 10 characters. a_stringneeds to be bigger.


8. If the intent of this line of code is to initialize a string, it is wrong. You should use
   eitherchar *quoteorchar quote[100].


9. No.


10. Yes. Although you can assign one pointer to another, you can’t assign one array to
    another. You should change the assignment to a string-copying command such as
    strcpy().

856 Appendix F

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