Electrical Power Systems Technology

Direct Current Power Systems 195

Solution:

Vr(p–p)

Vr(rms) = ———

2 × √ 3

1.2 V

= ———

3.46

Vr(rms) = 0.34 V

Figure 7-28. Filter capacitor operation: (A) Bridge rectifier circuit with filter ca-

pacitor, (8) Full-wave output waveform with no filter capacitor, (C) Full-wove

output waveform with filter capacitor across load, (D) Full-wave output wave-

form with filter capacitor across heavier (lower resistance) load