Programming and Problem Solving with Java

738

e.Overflowis the condition that occurs when the result of a calculation is greater

than the maximum number that can be represented in the computer.

11. a. x is 2314.38
    b.x is 2,314.38
    c. x is 2314.4
    d.x is 2,314.383

Chapter 12 Programming Warm-Up Exercises

1.final intNUM_SCHOOLS = 10 ;

final intNUM_SPORTS = 3 ;

// row/column 0 is football; row/column 1 is basketball;

// row/column 2 is volleyball

int[][] kidsInSports = new int[NUM_SCHOOLS][NUM_SPORTS];

double[][] costOfSports = new double[NUM_SPORTS][NUM_SCHOOLS];

a.intmostSoFar = 0 ;

for(intcolumn = 1 ; column < NUM_SCHOOLS; column++)

if(costOfSports[ 0 ][column] > costOfSports[ 0 ][mostSoFar])

mostSoFar = column;

// mostSoFar is the school that spent the most on football

b.intwhichSport = 0 ;

intlast = NUM_SCHOOLS - 1 ;

for(introw = 1 ; row < NUM_SPORTS; row++)

if(costOfSports[row][last] > costOfSports[whichSport][last])

whichSport = row;

// whichSport contains the sport that the last school spent the

// most on

c. intmostStudents = 0 ;

for(introw = 1 ; row < NUM_SCHOOLS; row++);

if(kidsInSports[row][ 1 ] > kidsInSports[mostStudents][ 1 ])

mostStudents = row;

// mostStudents is the school with the most students playing

// basketball

d.intwhichSport = 0 ;

for(intcolumn = 1 ; column < NUM_SPORTS; column++)

if(kidsInSports[ 2 ][column] > kidsInSports[ 2 ][whichSport])

whichSport = column;

// whichSport is the sport that the third school has the most

// students in

e.intsum = 0 ;

for(intcolumn = 0 ; column < NUM_SCHOOLS; column++)

sum = sum + costOfSports[ 2 ][column];

// sum contains the total amount spent on volleyball