5 Characters of Arbitrary Finite Groups 415is a diagonal matrix. Moreover, sinceT−^1 SkT=diag[ω 1 k,...,ωkn],ω 1 ,...,ωnare allm-th roots of unity. Thusχ(s)=ω 1 +···+ωnis a sum ofnm-th roots of unity. Since the inverse of a root of unityωis its complex
conjugateω ̄, it follows thatχ(s−^1 )=ω− 11 +···+ω−n^1 =χ(s).Now letGbe a group of finite orderg,andletρ:s→A(s)andσ:s→B(s)be
irreducible matrix representations ofGof degreesnandmrespectively. For anyn×m
matrixC, form the matrixT=∑
s∈GA(s)CB(s−^1 ).Sincetsruns through the elements ofGat the same time ass,A(t)T=TB(t) for everyt∈G.Therefore, by Schur’s lemma,T=Oifρis not equivalent toσandT=λIifρ=σ.
In particular, takeCto be any one of themnmatrices which have a single entry 1 and
all other entries 0. Then ifA=(αij),B=(βkl),weget∑s∈Gαij(s)βkl(s−^1 )={
0ifρ,σare inequivalent,
λjkδil ifρ=σ,whereδil = 1 or 0 according asi =lori = l(‘Kronecker delta’). Since for
(αij)=(βij)the left side is unchanged wheniis interchanged withkandjwith
l,wemusthaveλjk=λδjk. To determineλseti=l,j=kand sum with respect
tok. Since the matrices representingsands−^1 are inverse, we getg 1 =nλ. Thus
∑s∈Gαij(s)αkl(s−^1 )={
g/n ifj=kandi=l,
0otherwise.Ifμ,vrun through an index set for the inequivalent irreducible representations of
G, then the relations which have been obtained can be rewritten in the form∑s∈Gαij(μ)(s)α(klv)(s−^1 )={
g/nμ ifμ=v,j=k,i=l,
0otherwise.(5)
Theorthogonality relations(5) for the irreducible matrix elements have several corol-
laries:
(i)The functionsαij(μ):G→Care linearly independent.