1 Uniform Distribution 451If f is a continuous function of period 1 then, by the Weierstrass approximation
theorem, for anyε>0 there exists a trigonometric polynomialg(t)such that
|f(t)−g(t)|<εfor everyt∈I. Hence
∣
∣
∣
∣N− 1∑N
n= 1f({ξn})−∫
If(t)dt∣
∣
∣
∣
≤
∣
∣
∣
∣N
− 1∑N
n= 1(f({ξn})−g({ξn}))∣
∣
∣
∣+
∣
∣
∣
∣N
− 1∑N
n= 1g({ξn})−∫
Ig(t)dt∣
∣
∣
∣
+
∣
∣
∣
∣
∫
I(g(t)−f(t))dt∣
∣
∣
∣
< 2 ε+∣
∣
∣
∣N
− 1∑N
n= 1g({ξn})−∫
Ig(t)dt∣
∣
∣
∣
< 3 ε for all largeN.Thus (1) holds for every continuous functionfof period 1.
Finally, ifχα,βis the function defined in the proof of Theorem 1 then, for any
ε>0, there exist continuous functionsf 1 ,f 2 of period 1 such that
f 1 (t)≤χα,β(t)≤f 2 (t) for everyt∈Iand
∫
I(f 2 (t)−f 1 (t))dt<ε,from which it follows similarly that
N−^1
∑N
n= 1χα,β({ξn})→∫
Iχα,β(t)dt asN→∞.Thus the sequence(ξn)is uniformly distributed mod 1.
Weyl’s criterion, as Theorem 2 is usually called, immediately implies Bohl’s result:Proposition 3Ifξis irrational, the sequence(nξ)is uniformly distributed mod 1.
Proof For any nonzero integerh,
e(hξ)+e( 2 hξ)+···+e(Nhξ)=(e((N+ 1 )hξ)−e(hξ))/(e(hξ)− 1 ).Hence
∣
∣
∣
∣N− 1∑N
n= 1e(hnξ)∣
∣
∣
∣≤^2 |e(hξ)−^1 |− (^1) N− (^1) ,
and the result follows from Theorem 2.