Number Theory: An Introduction to Mathematics

(ff) #1
2 Partitions 547

We h av e


F(x)−G(x)
=


n≥ 0

(− 1 )nx^2 nq^5 n(n+^1 )/^2 {q−^2 n−x^2 q^2 (n+^1 )−q−n+xqn+^1 }/(q)n(xqn+^1 )∞

=



n≥ 0

(− 1 )nx^2 nq^5 n(n+^1 )/^2 {q−^2 n( 1 −qn)+xqn+^1 ( 1 −xqn+^1 )}/(q)n(xqn+^1 )∞

=



n≥ 1

(− 1 )nx^2 nq^5 n(n+^1 )/^2 −^2 n/(q)n− 1 (xqn+^1 )∞

+xq


n≥ 0

(− 1 )nx^2 nq^5 n(n+^1 )/^2 +n/(q)n(xqn+^2 )∞

=−x^2 q^3


n≥ 0

(− 1 )nx^2 nq^5 n(n+^1 )/^2 +^3 n/(q)n(xqn+^2 )∞

+xq


n≥ 0

(− 1 )nx^2 nq^5 n(n+^1 )/^2 +n/(q)n(xqn+^2 )∞

=xq


n≥ 0

(− 1 )n(xq)^2 nq^5 n(n+^1 )/^2 −n{ 1 −(xq)q^2 n+^1 }/(q)n(xqn+^2 )∞

=xqG(xq).

Similarly,


G(x)=


n≥ 0

(− 1 )nx^2 nq^5 n(n+^1 )/^2 {q−n−xqn+^1 }/(q)n(xqn+^1 )∞

=



n≥ 0

(− 1 )nx^2 nq^5 n(n+^1 )/^2 {q−n( 1 −qn)+ 1 −xqn+^1 }/(q)n(xqn+^1 )∞

=



n≥ 1

(− 1 )nx^2 nq^5 n(n+^1 )/^2 −n/(q)n− 1 (xqn+^1 )∞

+



n≥ 0

(− 1 )nx^2 nq^5 n(n+^1 )/^2 /(q)n(xqn+^2 )∞

=



n≥ 0

(− 1 )n(xq)^2 nq^5 n(n+^1 )/^2 −^2 n{ 1 −(xq)^2 q^2 (^2 n+^1 )}/(q)n(xqn+^2 )∞

=F(xq).

Combining this with the previous relation, we obtain


F(x)=F(xq)+xq F(xq^2 ).

But we have seen that thisq-difference equation has a unique holomorphic solution
f(x)such thatf( 0 )=1. HenceF(x)=f(x). 

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