208 GRAPHSHence y=mx+c=± 1 x+0, i.e. y=x and
y=−xare asymptotes.To determine any asymptotes parallel to the x-
andy-axes for the functionx^3 −xy^2 + 2 x− 9 =0:Equating the coefficient of the highest power ofx
term to zero gives 1=0 which is not an equation of
a line. Hence there is no asymptote parallel with the
x-axis.Equating the coefficient of the highest power ofy
term to zero gives−x=0 from which,x=0.Hencex= 0 ,y=xandy=−xare asymptotes for
the functionx^3 −xy^2 + 2 x− 9 = 0.Problem 12. Find the asymptotes for the func-tion y=x^2 + 1
xand sketch a graph of the
function.Rearrangingy=x^2 + 1
xgivesyx=x^2 +1.
Equating the coefficient of the highest powerxterm
to zero gives 1=0, hence there is no asymptote
parallel to thex-axis.
Equating the coefficient of the highest poweryterm
to zero givesx=0.
Hence there is an asymptote atx=0 (i.e. the
y-axis)To determine any other asymptotes we substitute
y=mx+cintoyx=x^2 +1 which gives
(mx+c)x=x^2 + 1
i.e. mx^2 +cx=x^2 + 1
and (m−1)x^2 +cx− 1 = 0Equating the coefficient of the highest powerxterm
to zero givesm− 1 =0, from whichm=1.
Equating the coefficient of the next highest powerx
term to zero givesc=0. Hencey=mx+c= 1 x+0,
i.e.y=xis an asymptote.A sketch ofy=
x^2 + 1
xis shown in Fig. 19.35.
It is possible to determine maximum/minimum
points on the graph (see Chapter 28).Since y=x^2 + 1
x=x^2
x+1
x=x+x−^1thendy
dx= 1 −x−^2 = 1 −1
x^2= 0for a turning point.Hence 1=1
x^2andx^2 =1, from which,x=±1.
Whenx=1,y=x^2 + 1
x=1 + 1
1= 2and whenx=−1,y=(−1)^2 + 1
− 1=− 2i.e. (1, 2) and (−1,−2) are the co-ordinates of theturning points.d^2 y
dx^2= 2 x−^3 =2
x^3; whenx=1,d^2 y
dx^2
is positive, which indicates a minimum point andwhenx=−1,d^2 y
dx^2is negative, which indicates a
maximum point, as shown in Fig. 19.35.Now try the following exercise.Exercise 88 Further problems on
asymptotesIn Problems 1 to 3, determine the asymptotes
parallel to thex- andy-axes1.y=x− 2
x+ 1[y=1,x=−1]2.y^2 =x
x− 3[x=3,y=1 andy=−1]3.y=x(x+3)
(x+2)(x+1)
[x=−1,x=−2 andy=1]In Problems 4 and 5, determine all the asymp-
totes- 8x− 10 +x^3 −xy^2 = 0
[x=0,y=xandy=−x]
5.x^2 (y^2 −16)=y
[y=4,y=−4 andx=0]
In Problems 6 and 7, determine the asymptotes
and sketch the curves6.y=x^2 −x− 4x+ (^1) [
x=−1,y=x−2,
see Fig. 19 .40, page 215
]
7.xy^2 −x^2 y+ 2 x−y= 5
[
x=0,y=0,y=x,
see Fig. 19 .41, page 215
]