Higher Engineering Mathematics

(Greg DeLong) #1
212 GRAPHS

(a) Squaring the equation givesx^2 = 4

[
1 −

(y

2

) 2 ]

and transposing givesx^2 = 4 −y^2 , i.e.
x^2 +y^2 = 4 .Comparing this equation with
x^2 +y^2 =a^2 shows thatx^2 +y^2 =4 is the equa-
tion of acirclehaving centre at the origin (0, 0)
and of radius 2 units.

(b) Transposing


y^2
8

= 2 x gives y= 4


x. Thus

y^2
8

= 2 xis the equation of aparabolahaving
its axis of symmetry coinciding with thex-axis
and its vertex at the origin of a rectangular
co-ordinate system.

(c)y= 6

(
1 −

x^2
16

) 1 / 2
can be transposed to

y
6

=

(
1 −

x^2
16

) 1 / 2
and squaring both sides gives

y^2
36

= 1 −

x^2
16

, i.e.

x^2
16

+

y^2
36

=1.

This is the equation of anellipse, centre at the
origin of a rectangular co-ordinate system, the
major axis coinciding with they-axis and being
2


36, i.e. 12 units long. The minor axis coin-
cides with the x-axis and is 2


16, i.e. 8
units long.

Problem 17. Describe the shape of the curves
represented by the following equations:

(a)

x
5

=

√[

1 +

(y

2

) 2 ]
(b)

y
4

=

15
2 x

(a) Since

x
5

=

√[

1 +

(y

2

) 2 ]

x^2
25

= 1 +

(y

2

) 2

i.e.

x^2
25


y^2
4

= 1

This is ahyperbolawhich is symmetrical about
both thex- andy-axes, the vertices being 2


25,
i.e. 10 units apart.
(With reference to Section 19.1 (vii),ais equal
to±5)

(b) The equation


y
4

=

15
2 x

is of the formy=

a
x

,

a=

60
2

=30.

This represents arectangular hyperbola, sym-
metrical about both thex- andy-axis, and lying
entirely in the first and third quadrants, similar
in shape to the curves shown in Fig. 19.9.

Now try the following exercise.

Exercise 89 Further problems on curve
sketching


  1. Sketch the graphs of (a)y= 3 x^2 + 9 x+


7
4
(b)y=− 5 x^2 + 20 x+50.
⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣
(a) Parabola with minimum
value at

(
−^32 ,− 5

)
and
passing through

(
0, 1^34

)
.
(b) Parabola with maximum
value at (2, 70) and passing
through (0, 50).

⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦

In Problems 2 to 8, sketch the curves depicting
the equations given.

2.x= 4

√[

1 −

(y

4

) 2 ]

[circle, centre (0, 0), radius 4 units]

3.


x=

y

(^9) [
parabola, symmetrical about
x-axis, vertex at (0, 0)
]
4.y^2 =
x^2 − 16
(^4) ⎡


hyperbola, symmetrical about
x- andy-axes, distance
between vertices 8 units along
x-axis



5.
y^2
5
= 5 −
x^2
2


ellipse, centre (0, 0), major axis
10 units alongy-axis, minor axis
2

10 units alongx-axis


6.x= 3

1 +y^2



hyperbola, symmetrical about
x- andy-axes, distance
between vertices 6 units along
x-axis


Free download pdf