378 INTEGRAL CALCULUS
At the points of intersection the co-ordinates of the
curves are equal. Sincey=x^2 theny^2 =x^4. Hence
equating they^2 values at the points of intersection:
x^4 = 8 x
from which, x^4 − 8 x= 0
and x(x^3 −8)= 0
Hence, at the points of intersection,x=0 andx=2.
Whenx=0,y=0 and whenx=2,y=4. The
points of intersection of the curves y=x^2 and
y^2 = 8 xare therefore at (0,0) and (2,4). A sketch is
shown in Fig. 38.8. Ify^2 = 8 xtheny=
√
8 x.
Shaded area
=
∫ 2
0
(√
8 x−x^2
)
dx=
∫ 2
0
(√
8
)
x
1
(^2) −x^2
)
dx
⎡
⎣
(√
8
)x^32
3
2
−
x^3
3
⎤
⎦
2
0
{√
8
√
8
3
2
−
8
3
}
−{ 0 }
16
3
−
8
3
8
3
= 2
2
3
square units
Figure 38.8
The volume produced by revolving the shaded area
about thex-axis is given by:
{(volume produced by revolvingy^2 = 8 x)
−(volume produced by revolvingy=x^2 )}
i.e.volume=
∫ 2
0
π(8x)dx−
∫ 2
0
π(x^4 )dx
=π
∫ 2
0
(8x−x^4 )dx=π
[
8 x^2
2
−
x^5
5
] 2
0
=π
[(
16 −
32
5
)
−(0)
]
=9.6πcubic units
Now try the following exercise.
Exercise 150 Further problems on volumes
- The curvexy=3 is revolved one revolution
about thex-axis between the limitsx=2 and
x=3. Determine the volume of the solid
produced. [1.5πcubic units] - The area between
y
x^2
=1 andy+x^2 =8is
rotated 360◦about thex-axis. Find the vol-
ume produced. [170^23 πcubic units]
- The curvey= 2 x^2 +3 is rotated about (a) the
x-axis between the limitsx=0 andx=3,
and (b) they-axis, between the same limits.
Determine the volume generated in each case.
[(a) 329.4π(b) 81π] - The profile of a rotor blade is bounded by the
linesx= 0 .2,y= 2 x,y=e−x,x=1 and the
x-axis. The blade thicknesstvaries linearly
withxand is given by:t=(1. 1 −x)K, where
K is a constant.
(a) Sketch the rotor blade, labelling the
limits.
(b) Determine, using an iterative method, the
value ofx, correct to 3 decimal places,
where 2x=e−x
(c) Calculate the cross-sectional area of the
blade, correct to 3 decimal places.
(d) Calculate the volume of the blade in terms
of K, correct to 3 decimal places.
[(b) 0.352 (c) 0.419 square units
(d) 0.222 K]
38.5 Centroids
Alaminais a thin flat sheet having uniform thick-
ness. Thecentre of gravityof a lamina is the point