382 INTEGRAL CALCULUSWhen areaPQRSis rotated about axisXXthe vol-
ume generated is that of the pulley. The centroid ofthe semicircular area removed is at a distance of4 r
3 π
from its diameter (see ‘Engineering Mathematics4thedition’, page 471), i.e.4(1.0)
3 π, i.e. 0.424 cm from
PQ. Thus the distance of the centroid fromXXis
5. 0 − 0 .424, i.e. 4.576 cm.
The distance moved through in one revolution by the
centroid is 2π(4.576) cm.
Area of semicircle=
πr^2
2=π(1.0)^2
2=π
2cm^2By the theorem of Pappus,volume generated=area×distance moved by
centroid=(π2)
(2π)(4.576).i.e.volume of metal removed=45.16 cm^3Mass of metal removed=density×volume=8000 kg m−^3 ×45. 16
106m^3= 0 .3613 kg or 361.3gvolume of pulley=volume of cylindrical disc
−volume of metal removed
=π(5.0)^2 (2.0)− 45. 16=111.9 cm^3Mass of pulley=density×volume=8000 kg m−^3 ×111. 9
106m^3=0.8952 kgor895.2 gNow try the following exercise.Exercise 152 Further problems on the the-
orem of Pappus- A right angled isosceles triangle having a
hypotenuse of 8 cm is revolved one revolution
about one of its equal sides as axis. Deter-
mine the volume of the solid generated using
Pappus’ theorem. [189.6 cm^3 ] - Using (a) the theorem of Pappus, and (b) inte-
gration, determine the position of the centroid
of a metal template in the form of a quadrant
of a circle of radius 4 cm. (The equation of a
circle, centre 0, radiusrisx^2 +y^2 =r^2 ).
⎡⎢
⎣On the centre line, distance
2 .40 cm from the centre,
i.e. at co-ordinates
(1.70, 1.70)⎤⎥
⎦- (a) Determine the area bounded by the curve
y= 5 x^2 , the x-axis and the ordinates
x=0 andx=3.
(b) If this area is revolved 360◦about (i) the
x-axis, and (ii) they-axis, find the vol-
umes of the solids of revolution produced
in each case.(c) Determine the co-ordinates of the cen-
troid of the area using (i) integral calcu-
lus, and (ii) the theorem of Pappus.
⎡⎢
⎣(a) 45 square units
(b) (i) 1215πcubic units
(ii) 202.5πcubic units
(c) (2.25, 13.5)⎤⎥
⎦- A metal disc has a radius of 7.0 cm and is
of thickness 2.5 cm. A semicircular groove of
diameter 2.0 cm is machined centrally around
the rim to form a pulley. Determine the vol-
ume of metal removed using Pappus’ theorem
and express this as a percentage of the origi-
nal volume of the disc. Find also the mass of
metal removed if the density of the metal is
7800 kg m−^3.
[64.90 cm^3 , 16.86%, 506.2 g]
For more on areas, mean and r.m.s. values, volumes
and centroids, see ‘Engineering Mathematics4th
edition’, Chapters 54 to 57.38.7 Second moments of area of
regular sectionsThefirst moment of areaabout a fixed axis of a
lamina of areaA, perpendicular distanceyfrom the
centroid of the lamina is defined asAycubic units.
Thesecond moment of areaof the same lamina as
above is given byAy^2 , i.e. the perpendicular distance