LINEAR REGRESSION 573J
Substitutinga 1 = 0 .586 in equation (1) gives:
855 = 7 a 0 +1400(0.586)i.e. a 0 =855 − 820. 4
7= 4. 94Thus the equation of the regression line of inductive
reactance on frequency is:
Y=4.94+0.586XProblem 2. For the data given in Problem 1,
determine the equation of the regression line of
frequency on inductive reactance, assuming a
linear relationship.In this case, the inductive reactance is the indepen-
dent variableXand the frequency is the dependent
variableY. From equations 3 and 4, the equation of
the regression line ofXonYis:
X=b 0 +b 1 Yand the normal equations are
∑
X=b 0 N+b 1∑
Yand∑
XY=b 0∑
Y+b 1∑
Y^2From the table shown in Problem 1, the simultaneous
equations are:
1400 = 7 b 0 + 855 b 1
212000 = 855 b 0 + 128725 b 1Solving these equations in a similar way to that in
Problem 1 gives:
b 0 =− 6. 15
and b 1 = 1 .69, correct to 3 significant figuresThus the equation of the regression line of frequency
on inductive reactance is:
X=−6.15+1.69YProblem 3. Use the regression equations cal-
culated in Problems 1 and 2 to find (a) the value
of inductive reactance when the frequency is
175 Hz and (b) the value of frequency whenthe inductive reactance is 250 ohms, assuming
the line of best fit extends outside of the given
co-ordinate values. Draw a graph showing the
two regression lines.(a) From Problem 1, the regression equation of
inductive reactance on frequency is
Y= 4. 94 + 0. 586 X. When the frequency,X,is
175 Hz,Y= 4. 94 + 0 .586(175)= 107 .5, correct
to 4 significant figures, i.e. the inductive reac-
tance is 107.5 ohms when the frequency is
175 Hz.
(b) From Problem 2, the regression equation of fre-
quency on inductive reactance is
X=− 6. 15 + 1. 69 Y. When the inductive reac-
tance,Y, is 250 ohms,
X=− 6. 15 + 1 .69(250)= 416 .4 Hz, correct to 4
significant figures, i.e. the frequency is416.4 Hz
when the inductive reactance is 250 ohms.The graph depicting the two regression lines is
shown in Fig. 60.2. To obtain the regression line
of inductive reactance on frequency the regression
line equationY= 4. 94 + 0. 586 Xis used, andX(fre-
quency) values of 100 and 300 have been selected
in order to find the correspondingYvalues. These
values gave the co-ordinates as (100, 63.5) and (300,
180.7), shown as pointsAandBin Fig. 60.2. Two
co-ordinates for the regression line of frequency on
inductive reactance are calculated using the equa-
tion X=− 6. 15 + 1. 69 Y, the values of inductive
reactance of 50 and 150 being used to obtain the
co-ordinate values. These values gave co-ordinatesDBA
C0 100 200 300 400 500
Frequency in hertz50100150200250300Inductive reactance in ohmsYXFigure 60.2