582 STATISTICS AND PROBABILITY
in the intervals:
mean±1 standard deviation,
mean±2 standard deviations,
or mean±3 standard deviations,
by using tables of the partial areas under the stan-
dardized normal curve given in Table 58.1 on
page 561. From this table, the area corresponding
to az-value of+1 standard deviation is 0.3413, thus
the area corresponding to±1 standard deviation
is 2×0.3413, that is, 0.6826. Thus the percentage
probability of a sampling statistic lying between the
mean±1 standard deviation is 68.26%. Similarly,
the probability of a sampling statistic lying between
the mean±2 standard deviations is 95.44% and
of lying between the mean±3 standard deviations
is 99.74%.
The values 68.26%, 95.44% and 99.74% are
called theconfidence levelsfor estimating a sam-
pling statistic. A confidence level of 68.26% is
associated with two distinct values, these being,
S−(1 standard deviation), i.e.S−σsand
S+(1 standard deviation), i.e.S+σs. These two
values are called theconfidence limitsof the esti-
mate and the distance between the confidence limits
is called theconfidence interval. A confidence inter-
val indicates the expectation or confidence of finding
an estimate of the population statistic in that interval,
based on a sampling statistic. The list in Table 61.1
is based on values given in Table 58.1, and gives
some of the confidence levels used in practice and
their associatedz-values; (some of the values given
are based on interpolation). When the table is used
in this context,z-values are usually indicated by ‘zc’
and are called theconfidence coefficients.
Table 61.1
Confidence level, % Confidence coefficient,zc
99 2.58
98 2.33
96 2.05
95 1.96
90 1.645
80 1.28
50 0.6745
Any other values of confidence levels and their asso-
ciated confidence coefficients can be obtained using
Table 58.1.
Problem 4. Determine the confidence coef-
ficient corresponding to a confidence level
of 98.5%.
98.5% is equivalent to a per unit value of 0.9850.
This indicates that the area under the standardized
normal curve between−zcand+zc, i.e. correspond-
ing to 2zc, is 0.9850 of the total area. Hence the
area between the mean value andzcis
0. 9850
2
i.e.
0.4925 of the total area. Thez-value correspond-
ing to a partial area of 0.4925 is 2.43 standard
deviations from Table 58.1. Thus,the confidence
coefficient corresponding to a confidence limit of
98.5% is 2.43.
(a) Estimating the mean of a population when the
standard deviation of the population is known
When a sample is drawn from a large population
whose standard deviation is known, the mean value
of the sample, x, can be determined. This mean
value can be used to make an estimate of the mean
value of the population,μ. When this is done, the
estimated mean value of the population is given as
lying between two values, that is, lying in the con-
fidence interval between the confidence limits. If a
high level of confidence is required in the estimated
value ofμ, then the range of the confidence interval
will be large. For example, if the required confidence
level is 96%, then from Table 61.1 the confidence
interval is from−zcto+zc, that is, 2× 2. 05 = 4. 10
standard deviations wide. Conversely, a low level
of confidence has a narrow confidence interval and a
confidence level of, say, 50%, has a confidence inter-
valof2×0.6745, that is 1.3490 standard deviations.
The 68.26% confidence level for an estimate of the
population mean is given by estimating that the pop-
ulation mean,μ, is equal to the same mean,x, and
then stating the confidence interval of the estimate.
Since the 68.26% confidence level is associated with
‘±1 standard deviation of the means of the sampling
distribution’, then the 68.26% confidence level for
the estimate of the population mean is given by:
x± 1 σx
In general, any particular confidence level can be
obtained in the estimate, by usingx±zcσx, where
zcis the confidence coefficient corresponding to the
particular confidence level required. Thus for a 96%
confidence level, the confidence limits of the pop-
ulation mean are given byx± 2. 05 σx. Since only
one sample has been drawn, the standard error of the
means,σx, is not known. However, it is shown in
Section 61.3 that
σx=
σ
√
N
√(
Np−N
Np− 1
)